Two strings X and Y of a sitar produce a beat frequency 4 Hz. When the tension of the string Y is slightly increased the beat frequency is found to be 2 Hz. If the frequency of X is 300 Hz, then the original frequency of Y was
Text Solution
Verified by ExpertsThe correct answer is:
A
x = beat frequency = 4 Hz, which is decreasing (4 → → 2)
after increasing the tension of the string y.
Also tension of wire y increasing so 
Hence 
Correct
Wrong
⇒ ⇒ 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two tuning forks when sounded together produced 4 beats/sec. The frequency of one fork is 256. The …
Beats are the result of
Two adjacent piano keys are struck simultaneously. The notes emitted by them have frequencies and …
A tuning fork of frequency 100 when sounded together with another tuning fork of unknown frequency …
A tuning fork sounded together with a tuning fork of frequency 256 emits two beats. On loading the …
If two tuning forks A and B are sounded together, they produce 4 beats per second. A is then slight…